A rectangle has a length of 25 cm and a width of 12.25 cm. A larger, similar rectangle has a width of 49 cm. What is the length of the largest rectangle?
We can set up a proportion to solve this problem. The length and width of the smaller rectangle are in a ratio of $\dfrac{25}{12.25} = \dfrac{100}{49}$. Let $x$ be the length of the larger rectangle. Therefore, $\dfrac{x}{49} = \dfrac{25}{12.25}$, and $x=\dfrac{49\cdot25}{12.25}=\dfrac{245}{0.49}=245\div0.49=\boxed{\textbf{(3)}\ 100 \textrm{ cm}}$.
