Red Sox designated hitter, David Ortiz, swings at a 0.15 kg baseball and accelerates it ar a rate of 3.0 times 10 to the power of four meters per second squared. How much force does Ortiz exert on the ball
To determine the force exerted by Ortiz on the ball, we can use Newton's second law of motion, which states that Force (F) = mass (m) * acceleration (a).
Given:
- Mass of the baseball (m) = 0.15 kg
- Acceleration (a) = 3.0 * 10^4 m/s^2
Plugging these values into the formula:
F = m * a
F = 0.15 kg * 3.0 * 10^4 m/s^2
Using scientific notation multiplication:
F = 4.5 * 10^3 kg * m/s^2
Hence, Ortiz exerts a force of 4.5 * 10^3 N on the baseball.