In a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. What is the total momentum of the system after the collision?(1 point)
Responses
42 kg-m/s
42 kg-m/s
54 kg-m/s
54 kg-m/s
66 kg-m/s
66 kg-m/s
12 kg-m/s
To calculate the total momentum of the system after the collision, we need to find the individual momenta of both objects and add them together.
The momentum (p) of an object can be calculated using the formula:
p = mass * velocity
For the first object:
mass1 = 10 kg
velocity1 = 5.4 m/s
p1 = mass1 * velocity1 = 10 kg * 5.4 m/s = 54 kg-m/s
For the second object:
mass2 = 12 kg
velocity2 = -3.5 m/s (since it is moving in the opposite direction)
p2 = mass2 * velocity2 = 12 kg * (-3.5 m/s) = -42 kg-m/s
The total momentum of the system is the sum of the individual momenta:
total momentum = p1 + p2 = 54 kg-m/s + (-42 kg-m/s) = 12 kg-m/s
Therefore, the total momentum of the system after the collision is 12 kg-m/s.