Solve for y. 2y^2-17y+39=(y-3)^2
To solve for y, we can start by expanding (y-3)^2.
(y-3)^2 = y^2 - 6y + 9
Now we can substitute this into our equation:
2y^2 - 17y + 39 = y^2 - 6y + 9
To simplify, let's bring all the terms to one side of the equation:
2y^2 - y^2 - 17y + 6y + 39 - 9 = 0
y^2 - 11y + 30 = 0
Next, we attempt to factorize.
(y - 5)(y - 6) = 0
Now we can set each factor equal to zero and solve for y.
y - 5 = 0 or y - 6 = 0
y = 5 or y = 6
Therefore, the solutions for y are 5 and 6.