If △XYZ∼△AYB
, and YB¯¯¯¯¯¯¯¯=16
ft, YA¯¯¯¯¯¯¯¯=25
ft, and YZ¯¯¯¯¯¯¯=88
ft, then what is the length of YX¯¯¯¯¯¯¯¯
?(1 point)
Responses
137.5 ft
137.5 ft
162.5 ft
162.5 ft
90.25 ft
90.25 ft
125.25 ft
125.25 ft
We can use the concept of similar triangles to find the length of YX. Since △XYZ∼△AYB, we can set up the proportion:
(YX/YA) = (YZ/YB)
Substituting the given values:
(YX/25) = (88/16)
Cross-multiplying:
16YX = 25 * 88
Dividing both sides by 16:
YX = (25 * 88) / 16
Simplifying:
YX = 137.5 ft
Therefore, the length of YX¯¯¯¯¯¯¯¯ is 137.5 ft.