Let the first entire population be -10 0 10 20 30 and second 8 9 10 11 12
Calculate the mean,media,mode range variance and also compare there mean
To calculate the mean of each population, we add up all the values and divide by the total number of values:
First population: (-10 + 0 + 10 + 20 + 30) / 5 = 50 / 5 = 10
Second population: (8 + 9 + 10 + 11 + 12) / 5 = 50 / 5 = 10
The mean of both populations is 10.
To calculate the median, we arrange the values in ascending order and find the middle value:
First population: -10, 0, 10, 20, 30
Median = 10
Second population: 8, 9, 10, 11, 12
Median = 10
The median of both populations is 10.
To calculate the mode, we find the value(s) that occur(s) most frequently:
First population: No mode as all values occur only once
Second population: Mode = 10
The mode of the second population is 10.
To calculate the range, we subtract the lowest value from the highest value:
First population: 30 - (-10) = 40
Second population: 12 - 8 = 4
The range of the first population is 40, and the range of the second population is 4.
To calculate the variance, we need to find the difference between each value and the mean, square each difference, and calculate the average of those squared differences:
First population: (-10 - 10)^2 + (0 - 10)^2 + (10 - 10)^2 + (20 - 10)^2 + (30 - 10)^2 = 800
Variance = 800 / 5 = 160
Second population: (8 - 10)^2 + (9 - 10)^2 + (10 - 10)^2 + (11 - 10)^2 + (12 - 10)^2 = 2
Variance = 2 / 5 = 0.4
The variance of the first population is 160, and the variance of the second population is 0.4.
Comparing the means of both populations, we can conclude that they are both equal at 10.