There are two types of tickets to attend the awards dinner-silver and gold. The gold tickets are $8 more than the silver. If Patrick bought 10 tickets on each lvl and spent a total of $140. Find the price of each ticket.
Let's assume the price of a silver ticket is x dollars.
Therefore, the price of a gold ticket would be x + $8.
Patrick bought 10 silver tickets, so the cost of the silver tickets would be 10x dollars.
Patrick also bought 10 gold tickets, so the cost of the gold tickets would be 10(x + $8) dollars.
The total cost of all the tickets is given as $140:
10x + 10(x + $8) = $140
10x + 10x + $80 = $140
20x + $80 = $140
20x = $140 - $80
20x = $60
Dividing both sides of the equation by 20, we get:
x = $60 / 20
x = $3
Therefore, the price of each silver ticket is $3, and the price of each gold ticket is $3 + $8 = $<<3+8=11>>11. Answer: \boxed{3}.