How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
KE=12mv2
(1 point)
Responses
151.2 J
151.2 J
266.5 J
266.5 J
35.9 J
35.9 J
1.3 J
To calculate the difference in kinetic energy, we will first find the kinetic energy of the bowling ball rolling at 16 mph and then subtract the kinetic energy of the bowling ball rolling at 14 mph.
The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object in kilograms and v is the velocity of the object in meters per second.
First, let's calculate the kinetic energy of the bowling ball rolling at 16 mph (7.1 m/s):
KE1 = 1/2 * 6 kg * (7.1 m/s)^2
KE1 = 1/2 * 6 kg * 50.41 m^2/s^2
KE1 = 6.3 kg * 50.41 m^2/s^2
KE1 = 302.46 J
Next, let's calculate the kinetic energy of the bowling ball rolling at 14 mph (6.2 m/s):
KE2 = 1/2 * 6 kg * (6.2 m/s)^2
KE2 = 1/2 * 6 kg * 38.44 m^2/s^2
KE2 = 3 kg * 38.44 m^2/s^2
KE2 = 115.32 J
Now, let's find the difference in kinetic energy:
Difference = KE1 - KE2
Difference = 302.46 J - 115.32 J
Difference = 187.14 J
Therefore, the bowling ball has 187.14 J more kinetic energy when rolling at 16 mph compared to rolling at 14 mph.