A small ball with a mass of 0.7 kg and a velocity of 13 m/s hits another ball with the same mass. The first ball stops moving, and the of the third ball
Your question seems to be incomplete. I assume you meant to ask for the velocity of the third ball after the collision.
To solve this, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision, assuming there are no external forces.
The initial momentum of the system is given by the product of the mass and velocity of the first ball:
Initial momentum = mass * velocity = 0.7 kg * 13 m/s = 9.1 kg·m/s
Since the first ball stops moving after the collision, its final momentum is zero. So, the total momentum after the collision is only contributed by the second and third balls.
Let's assume the final velocities of both balls are v2 and v3 for the second and third balls, respectively.
The final momentum of the system is given by the sum of the momentum of the second and third balls:
Final momentum = mass of second ball * velocity of second ball + mass of third ball * velocity of third ball
Since both balls have the same mass of 0.7 kg, we can rewrite the equation as:
Final momentum = 0.7 kg * v2 + 0.7 kg * v3
Equating the initial and final momentum, we have:
9.1 kg·m/s = 0.7 kg * v2 + 0.7 kg * v3
Without more information about the collision (e.g., whether it is elastic or inelastic), we cannot determine the specific values of v2 and v3. The velocities of the second and third balls after the collision are dependent on the interaction between the two balls, such as the angle of collision, restitution coefficient, etc.
Therefore, we need more information or assumptions about the nature of the collision to determine the velocity of the third ball after the collision.