# What is the equation of an ellipse with a center (-4,2) and a horizonal major axis?

I know the equation is x^2/a^2+y^2/b^2 and that's all.

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you will have to give more information.

With only the centre (-4,2) all we can say is

(x+4)^2/a^2 + (y-2)^2/b^2 = 1

## To find the equation of an ellipse with a horizontal major axis and a center at (-4,2), we need to know the lengths of the major and minor axes.

Let's assume the length of the major axis is 2a and the length of the minor axis is 2b.

Since the major axis is horizontal, the equation will be in the form:

(x - h)^2 / a^2 + (y - k)^2 / b^2 = 1

where (h, k) is the center of the ellipse.

In this case, the center is (-4,2), so our equation becomes:

(x + 4)^2 / a^2 + (y - 2)^2 / b^2 = 1

To find the values of a and b, we need additional information about the ellipse, such as the length of the major axis or the distance from the center to one of the foci.