In a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. What is the total momentum of the system after the collision?(1 point)
54 kg-m/s%0D%0A54 kg-m/s%0D%0A%0D%0A42 kg-m/s%0D%0A42 kg-m/s%0D%0A%0D%0A66 kg-m/s%0D%0A66 kg-m/s%0D%0A%0D%0A12 kg-m/s
To calculate the total momentum of the system after the collision, we need to use the law of conservation of momentum. According to this law, the total momentum of a closed system before and after a collision is always conserved.
The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, the momentum of the first object before the collision is (10 kg) * (5.4 m/s) = 54 kg-m/s, while the momentum of the second object before the collision is (12 kg) * (-3.5 m/s) = -42 kg-m/s (since the second object is moving in the opposite direction, we assign a negative sign to its velocity).
The total momentum before the collision is the sum of the momenta of the individual objects, which is 54 kg-m/s + (-42 kg-m/s) = 12 kg-m/s.
Since the law of conservation of momentum states that the total momentum before and after the collision must be equal, the total momentum after the collision must also be 12 kg-m/s.
Therefore, the correct answer is 12 kg-m/s.