if AE=3x-6, DE=6y-12, EC=2x+2 and EB=2y+24 find the values of x and y
To find the values of x and y, we need to use the fact that the sum of the lengths of the segments around point E is equal to the length of segment EC.
AE + DE + EC + EB = EC
Substituting the given values:
(3x - 6) + (6y - 12) + (2x + 2) + (2y + 24) = 2x + 2
Combine like terms:
3x - 6 + 6y - 12 + 2x + 2 + 2y + 24 = 2x + 2
Simplifying further:
5x + 8y + 6 = 2x + 2
Subtract 2x from both sides:
5x - 2x + 8y + 6 = 2
Combine like terms:
3x + 8y + 6 = 2
Subtract 6 from both sides:
3x + 8y = -4
So the equation we have is 3x + 8y = -4.
Without additional information or equations, we cannot solve for the values of x and y.