Find the volume of a right circular cone that has a height of 5.9 in and a base with a diameter of 11.2 in. Round your answer to the nearest tenth of a cubic inch.
The radius of the base of the cone is half of the diameter, so the radius is 11.2 in / 2 = <<11.2/2=5.6>>5.6 in.
The formula for the volume of a cone is V = (1/3)πr²h, so V = (1/3)π(5.6 in)²(5.9 in) = 228.9324 in³.
Rounding to the nearest tenth of a cubic inch, the volume is 228.9 in³. Answer: \boxed{228.9}.