Question 1 (1 point)
The volume of a gas is 6.50 L when its pressure is 4.0 atm. If the temperature of the gas does not change, what is the pressure when its volume is changed to 8.00 L?
a
208 atm
b
3.25 atm
c
13.0 atm
d
5.33 atm
According to Boyle's Law, the pressure and volume of a gas are inversely proportional, assuming constant temperature. Mathematically, this can be expressed as:
P1 * V1 = P2 * V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Plugging in the given values:
P1 = 4.0 atm
V1 = 6.50 L
V2 = 8.00 L
Using the equation, we can solve for P2:
P2 = (P1 * V1) / V2
P2 = (4.0 atm * 6.50 L) / 8.00 L
P2 = 26.0 atm / 8.00 L
P2 = 3.25 atm
Therefore, the answer is:
b) 3.25 atm