Construct the line perpendicular to Modifying above NO with bar at point P.

A line segment is labeled with points N, P, and O from left to right.
(1 point)
Responses

A line segment N O is intersected by a perpendicular line at point P, between N and O, but slightly closer to O. Two compass lines intersect at P. The compass line on the left has N P as its radius and the compass line on the right has P O as its radius.
Image with alt text: A line segment N O is intersected by a perpendicular line at point P, between N and O, but slightly closer to O. Two compass lines intersect at P. The compass line on the left has N P as its radius and the compass line on the right has P O as its radius.

Points upper N, upper P, and upper O are plotted along with two overlapping compass points at point upper P.Point upper N lies on the left-most part of the horizontal line. Point upper P is at the center, where the horizontal and vertical lines intersect. Two pairs of crossed, curves lines indicate compass points and overlap at point upper P. One pair points vertically; the other points horizontally. Point upper O lies at the right-most part the horizontal line.
Image with alt text: Points upper N, upper P, and upper O are plotted along with two overlapping compass points at point upper P. Point upper N lies on the left-most part of the horizontal line. Point upper P is at the center, where the horizontal and vertical lines intersect. Two pairs of crossed, curves lines indicate compass points and overlap at point upper P. One pair points vertically; the other points horizontally. Point upper O lies at the right-most part the horizontal line.

Points upper N, upper P, and upper O are plotted with compass marks and compass points surrounding point upper P.Point upper N lies at the left-most part of the horizontal line. Point upper P is in the center, where the vertical and horizontal lines intersect. To the left and right of point upper P are curved compass marks. Above and below point upper P, there are crossed, curved lines indicating compass points. Point upper O lies on the right-most part of the horizontal line.
Image with alt text: Points upper N, upper P, and upper O are plotted with compass marks and compass points surrounding point upper P. Point upper N lies at the left-most part of the horizontal line. Point upper P is in the center, where the vertical and horizontal lines intersect. To the left and right of point upper P are curved compass marks. Above and below point upper P, there are crossed, curved lines indicating compass points. Point upper O lies on the right-most part of the horizontal line.

Points upper N, upper P, and upper O are plotted along with two compass points.Point upper N lies on the left-most part of the horizontal line. Point upper P lies at the center where the horizontal and vertical lines intersect. Two crossed, curved lines meet at point upper P, indicating a compass point. Directly above point upper P lie two more curved, crossed lines. Point upper O lies at the right-most part of the horizontal line.
Image with alt text: Points upper N, upper P, and upper O are plotted along with two compass points. Point upper N lies on the left-most part of the horizontal line. Point upper P lies at the center where the horizontal and vertical lines intersect. Two crossed, curved lines meet at point upper P, indicating a compass point. Directly above point upper P lie two more curved, crossed lines. Point upper O lies at the right-most part of the horizontal line.
Skip to navigation

The line perpendicular to NO at point P can be constructed by using a compass and drawing two arcs.

1. Place the compass point at point N and draw an arc that intersects line NO.
2. Without changing the compass radius, place the compass point at point O and draw another arc that intersects the first arc.
3. Label the intersection point of the two arcs as P.
4. Use a straightedge or ruler to draw a line through point P, perpendicular to line NO. This line is the perpendicular line to NO at point P.

1, 2, 3 or 4

The correct response is 3.