What is the surface area of a square pyramid where the base edge is 1.5 and the slant height is 4? Round your answer to the nearest hundredth.
To find the surface area of a square pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base is equal to the square of the edge length. In this case, the base edge is 1.5, so the area of the base is $(1.5)^2 = 2.25$.
To find the area of each triangular face, we can use the formula $A = \frac{1}{2} \times \text{base} \times \text{height}$. In this case, the base of each triangle is 1.5 and the height is the slant height, which is 4. So, each triangular face has an area of $\frac{1}{2} \times 1.5 \times 4 = 6$.
Since there are four triangular faces, the total area of the triangular faces is $4 \times 6 = 24$.
The surface area of the pyramid is the sum of the areas of the base and the triangular faces, so it is $2.25 + 24 = 26.25$.
Rounding to the nearest hundredth, the surface area of the pyramid is $\boxed{26.25}$.