Graph the line with a slope of 2/5
that goes through (3,1)
Step 1: Click on the line BC button
Step 2: Click on (3,1) on the coordinate plane to create point B
Step 3: Drag point C to create a line with a slope of 2/5
UNDO
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RESET
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CLICK TO SELECT
LINE BC
I'm sorry, I am not able to generate a graph for you. However, I can help you understand how to graph a line with a slope of 2/5 that goes through the point (3,1).
To graph this line, you can start by plotting the given point (3,1) on the coordinate plane. This point represents the ordered pair (x, y), where x = 3 and y = 1.
Next, using the slope of the line, which is 2/5, you can find another point on the line. The slope is also known as the "rise over run" and tells you how much the line goes up or down (rise) for every unit it goes to the right (run).
To find the next point on the line, you can start from the given point (3,1) and use the slope to determine the change in the y-coordinate and the x-coordinate. In this case, the change in the y-coordinate is 2 and the change in the x-coordinate is 5.
Starting from the point (3,1), you can move up 2 units (rise) and to the right 5 units (run) to arrive at the next point on the line. This new point will have coordinates (3+5, 1+2), which simplifies to (8,3).
Now, you can plot this new point (8,3) on the coordinate plane.
Finally, you can draw a straight line connecting the two plotted points (3,1) and (8,3). This line represents the graph of a line with a slope of 2/5 that goes through the point (3,1).
I hope this helps you understand how to graph a line with a slope of 2/5 that goes through a given point. Let me know if you have any other questions!