Solve the formula for the specified variable.

s=2ðrh + 2ðr^2 for h

f= (9/5)c+32 for c

A=P(1+nr) for r

for H i don't know what that notation is so I'll leave that alone and maybe someone else can help you with that

for c, there won't be a definite number but rather another function.

f=(9/5)c+32
f-32= (9/5)c divide over to get c
(f-32)/(9/5)= c

-just flip 9/5 and multiply it to f-32 (I'll leave that to you (If you need help just ask and I'll be glad to =D )

~for r

A=P(1+nr)
A/P= 1 + nr
(A/P)-1= nr
[(A/P)-1]/n= r

## To solve the given formulas for the specified variable, follow these steps:

1. Solve for h in the formula s=2πrh + 2πr²:

s = 2πrh + 2πr²

Subtract 2πr² from both sides:
s - 2πr² = 2πrh

Divide both sides by 2πr:
(s - 2πr²)/(2πr) = h

Simplify the expression on the left side, if possible.

2. Solve for c in the formula f = (9/5)c + 32:

f = (9/5)c + 32

Subtract 32 from both sides:
f - 32 = (9/5)c

Multiply both sides by (5/9) to isolate c:
(f - 32)(5/9) = c

Simplify the expression on the left side, if possible.

3. Solve for r in the formula A = P(1 + nr):

A = P(1 + nr)

Divide both sides by P:
A/P = 1 + nr

Subtract 1 from both sides:
(A/P) - 1 = nr

Divide both sides by n:
[(A/P) - 1]/n = r

Simplify the expression on the left side, if possible.

Note: For the variable H in the first formula, I'm unable to provide assistance as I'm not familiar with the notation you mentioned. Please seek guidance from someone else for solving that specific problem.