In a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. What is the total momentum of the system after the collision?(1 point)
Responses
12 kg-m/s
12 kg-m/s
42 kg-m/s
42 kg-m/s
66 kg-m/s
66 kg-m/s
54 kg-m/s
To find the total momentum of the system after the collision, we need to find the individual momenta of each object and add them together.
The momentum of an object is given by the formula: momentum = mass * velocity.
For the first object with a mass of 10 kg and a velocity of 5.4 m/s, its momentum is 10 kg * 5.4 m/s = 54 kg-m/s.
For the second object with a mass of 12 kg and a velocity of -3.5 m/s (since it is moving in the opposite direction), its momentum is 12 kg * (-3.5 m/s) = -42 kg-m/s.
To find the total momentum, we add the individual momenta together: 54 kg-m/s + (-42 kg-m/s) = 12 kg-m/s.
Therefore, the total momentum of the system after the collision is 12 kg-m/s.