What is the surface area of a square pyramid where the base edge is 8 ft. and the slant height is 16 ft.?(1 point)Responses 512 ft.2512 ft. squared 256 ft.2256 ft. squared 320 ft.2320 ft. squared 128 ft.2
The surface area of a square pyramid can be found by adding the areas of the base and the four triangular faces.
The area of the base of the square pyramid, which is a square, is (base edge)^2 = (8 ft)^2 = 64 ft^2.
The area of each triangular face can be found using the formula for the area of a triangle: (1/2) * base * height. In this case, the base is the base edge of the pyramid (8 ft) and the height is the slant height of the pyramid (16 ft).
The area of each triangular face is (1/2) * (8 ft) * (16 ft) = 64 ft^2.
Since there are four triangular faces, the total surface area is:
64 ft^2 + 4 * 64 ft^2 = 64 ft^2 + 256 ft^2 = 320 ft^2.
Therefore, the correct answer is: 320 ft^2.