Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point) Responses 795 N to the north and 855 N to the east 795 N to the north and 855 N to the east 795 N to the south and 855 N to the west 795 N to the south and 855 N to the west 855 N to the north and 795 N to the east 855 N to the north and 795 N to the east 855 N to the south and 759 N to the west
To find the total north-south net forces, we need to subtract the southward force of friction from the northward force applied by the worker. The total north-south net force is 960 N (force applied by the worker) - 105 N (southward force of friction) = 855 N to the north.
To find the total east-west net forces, we need to subtract the westward force of friction from the eastward force applied by the worker. The total east-west net force is 875 N (force applied by the worker) - 80 N (westward force of friction) = 795 N to the east.
Therefore, the correct answer is 855 N to the north and 795 N to the east.