A blue and a green billiard ball, each with a mass of 0.15 kg, collide directly. Before the collision, the blue ball had a speed of 3 m/s while the green ball had a speed of 2 m/s. After the collision, the blue ball stays in place while the green ball continues in motion.
In 3-4 sentences, represent the situation before and after the collision and calculate the speed of the green ball after the collision. Be sure to discuss direction.
Before the collision, the blue and green balls have different speeds and are moving in the same direction. After the collision, the blue ball comes to a stop and the green ball continues in motion. Since the blue ball stops completely, its final speed is 0 m/s. Using conservation of momentum, we can calculate the velocity of the green ball after the collision: 0.15 kg × 3 m/s + 0.15 kg × 2 m/s = 0.15 kg × v, where v is the final velocity of the green ball. Solving for v, we get v = 3 m/s. Therefore, the speed of the green ball after the collision is 3 m/s in the same direction as its initial velocity.
