In a closed system, an object with a mass of 10 kg moves at a velocity of 5.4 m/s. It collides with a second object that has a mass of 12 kg and that is moving in the opposite direction with a velocity of 3.5 m/s. What is the total momentum of the system after the collision?(1 point)
Responses
42 kg-m/s
42 kg-m/s
66 kg-m/s
66 kg-m/s
12 kg-m/s
12 kg-m/s
54 kg-m/s
To find the total momentum of the system after the collision, we can use the conservation of momentum principle, which states that the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is calculated by multiplying its mass by its velocity (p = m * v).
The momentum before the collision can be calculated as follows:
Momentum of object 1 = mass of object 1 * velocity of object 1
= 10 kg * 5.4 m/s
= 54 kg-m/s
Momentum of object 2 = mass of object 2 * velocity of object 2
= 12 kg * (-3.5 m/s) (note the negative sign since the object is moving in the opposite direction)
= -42 kg-m/s
Total momentum before the collision = momentum of object 1 + momentum of object 2
= 54 kg-m/s + (-42 kg-m/s)
= 12 kg-m/s
Therefore, the total momentum of the system after the collision is 12 kg-m/s.