A line passes through the point a(2,-5) and has a slope of 6
Write an equation in point-slope form for this line.
The point-slope form of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.
Using the given information, we have the point (x1, y1) = (2, -5) and the slope m = 6. Plugging these values into the point-slope form equation, we get:
y - (-5) = 6(x - 2)
Simplifying this equation gives:
y + 5 = 6x - 12
Now, rearrange the equation to have y on one side:
y = 6x - 12 - 5
Simplifying further gives the final equation:
y = 6x - 17
Therefore, the equation in point-slope form for the line passing through the point (2, -5) with a slope of 6 is y = 6x - 17.