Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise?
(1 point)
Responses
(−4, 2)
left parenthesis negative 4 comma 2 right parenthesis
(4,−2)
left parenthesis 4 comma negative 2 right parenthesis
(−2,−4)
left parenthesis negative 2 comma negative 4 right parenthesis
(−4,−2)
left parenthesis negative 4 comma negative 2 right parenthesis
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To rotate a point counterclockwise by 270 degrees, we can imagine the point being rotated around the origin (0,0).
Since the point A (2, 4) is in Quadrant I, when rotating counterclockwise by 270 degrees, it will end up in Quadrant II.
A 270-degree rotation will result in the x-coordinate becoming the negative y-coordinate and the y-coordinate becoming the x-coordinate with the same sign.
Therefore, the new point will be (-4, 2).