# A small primary school has a total enrolment of 50 students. A total of 20 of these play hockey, 18 play netball and 10 play both hockey and netball. How many students play neither hockey nor netball?

Of the 38 who play netball or hockey, ten play both. That makes 28 who are players. So, of the fifty, the remaining are not sports players.

10+18+20=48
50-48=2

## To find out how many students play neither hockey nor netball, we need to subtract the number of students who play either hockey or netball from the total number of students.

Given:
Total enrolment = 50
Number of students who play hockey = 20
Number of students who play netball = 18
Number of students who play both hockey and netball = 10

To determine the number of students who play neither hockey nor netball, we need to find the number of students who play either hockey or netball.

We can do this by adding the number of students who play hockey and the number of students who play netball, and then subtracting the number of students who play both.

Number of students who play either hockey or netball = Number of students who play hockey + Number of students who play netball - Number of students who play both

Number of students who play either hockey or netball = 20 + 18 - 10 = 28

Now, to find the number of students who play neither hockey nor netball, we subtract the number of students who play either hockey or netball from the total number of students.

Number of students who play neither hockey nor netball = Total enrolment - Number of students who play either hockey or netball

Number of students who play neither hockey nor netball = 50 - 28 = 22

Therefore, there are 22 students who play neither hockey nor netball in the small primary school.