(6x^3+4x^2+15x^4-9+3x)divided (-3x^2-2)
To divide (6x^3 + 4x^2 + 15x^4 - 9 + 3x) by (-3x^2 - 2), we use long division.
5x^2 - 2
-------------
(-3x^2 - 2) │15x^4 + 4x^2 + 6x - 9 + 3x
15x^4 + 10x^2
-----------------
-6x^2 + 6x - 9 + 3x
-6x^2 - 4
--------------------
9x - 5
Thus, (6x^3 + 4x^2 + 15x^4 - 9 + 3x) ÷ (-3x^2 - 2) = 5x^2 - 2 with a remainder of 9x - 5.