Given point A (2, 4) on the triangle quadrant. where is the new point if the triangle is rotated 270 degrees counterclockwise
To rotate a point counterclockwise, we need to apply a rotation matrix. The rotation matrix for a counterclockwise rotation of 270 degrees is:
[ cos(270°), -sin(270°) ]
[ sin(270°), cos(270°) ]
Applying this matrix to the point A(x, y), we get:
[ cos(270°), -sin(270°) ] * [ 2 ] [ -4 ]
[ sin(270°), cos(270°) ] [ 4 ] = [ 2 ]
Simplifying, we find that the new point is (-4, 2).