Find the first four terms of the sequence given by the following
^an=4(2)^n-1 n=1,2,3...
To find the first four terms of the sequence, plug in the values of n from 1 to 4 into the formula an = 4(2)^(n-1):
For n = 1:
a1 = 4(2)^(1-1) = 4(2)^0 = 4(1) = 4
For n = 2:
a2 = 4(2)^(2-1) = 4(2)^1 = 4(2) = 8
For n = 3:
a3 = 4(2)^(3-1) = 4(2)^2 = 4(4) = 16
For n = 4:
a4 = 4(2)^(4-1) = 4(2)^3 = 4(8) = 32
Therefore, the first four terms of the sequence are 4, 8, 16, and 32.