f the farm has 30 chickens and cows, and there are 82 chicken and cow legs all together, then how many chickens and how many cows could the farm have?
Let's assume that the number of chickens is x and the number of cows is y.
Since a chicken has 2 legs and a cow has 4 legs, we can create two equations based on the given information:
Equation 1: x + y = 30 (the total number of chickens and cows is 30)
Equation 2: 2x + 4y = 82 (the total number of legs is 82)
To solve these equations, we can use the substitution method. First, we solve Equation 1 for x:
x = 30 - y
Substitute this expression for x in Equation 2:
2(30 - y) + 4y = 82
60 - 2y + 4y = 82
2y = 82 - 60
2y = 22
y = 22 / 2
y = 11
Now we can substitute the value of y back into Equation 1:
x + 11 = 30
x = 30 - 11
x = 19
Therefore, there could be 19 chickens and 11 cows on the farm.