Find the first four terms of the sequence given by the following.
^an=2(4)^n-1, n=1,2,3
To find the first four terms of the sequence, we substitute the given values of n into the given formula.
For n = 1:
a1 = 2(4)^1-1
a1 = 2(4)^0
a1 = 2(1)
a1 = 2
For n = 2:
a2 = 2(4)^2-1
a2 = 2(4)^1
a2 = 2(4)
a2 = 8
For n = 3:
a3 = 2(4)^3-1
a3 = 2(4)^2
a3 = 2(16)
a3 = 32
Therefore, the first four terms of the sequence are 2, 8, 32.