Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
Responses
55.55 yd.2
55.55 yd. 2
43.31 yd.2
43.31 yd. 2
72.52 yd.2
72.52 yd. 2
66 yd.2
To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.
First, let's find the area of the base. The base of the pyramid is a rectangle with length (l) and width (w), so the area of the base is l * w = 8 yd. * 4 yd. = 32 yd².
Next, let's find the area of the four triangular faces. Each triangular face has a base (l) and height (h), so the area of each triangular face is (1/2) * l * h = (1/2) * 8 yd. * 2 yd. = 8 yd².
Since there are four triangular faces, the total area of the four triangular faces is 4 * 8 yd² = 32 yd².
Finally, let's find the sum of the base area and the area of the four triangular faces: 32 yd² + 32 yd² = 64 yd².
Therefore, the surface area of the rectangular pyramid is 64 yd².
So, the correct answer is not listed.