# write a balanced chemical equation for calcium nitate plus sulfuric acid produces calcium sulphate and ?

This is a metathetical reaction, I think more properly called a double displacement reaction now. Just change + and - partners.

Ca(NO3)2 + H2SO4 ==> CaSO4 + HNO3. I will let you balance it.

## To balance the equation:

Ca(NO3)2 + H2SO4 → CaSO4 + HNO3

Let's start by checking the number of each type of atom on both sides of the equation:

Calcium (Ca): 1 on the left, 1 on the right

Nitrogen (N): 2 on the left, 1 on the right

Oxygen (O): 6 on the left, 5 on the right

Hydrogen (H): 2 on the left, 1 on the right

Sulfur (S): 1 on the left, 1 on the right

To balance the equation, we can start by balancing the atoms that appear in only one compound on each side. In this case, we can balance the sulfur by ensuring that there is one sulfate ion (SO4) on the product side:

Ca(NO3)2 + H2SO4 → CaSO4 + HNO3

Next, let's balance the nitrogen by putting a coefficient of 2 in front of HNO3:

Ca(NO3)2 + H2SO4 → CaSO4 + 2HNO3

Now, we have an imbalance of oxygen. The left side has 14 oxygen atoms (from the two NO3 groups and two hydroxide groups from H2SO4), but the right side only has 4 from calcium sulfate.

To balance this, we can put a coefficient of 7/2 in front of the H2SO4 compound, which will give us 7 oxygen atoms on the left:

Ca(NO3)2 + 7/2H2SO4 → CaSO4 + 2HNO3

To simplify the equation, we can multiply all coefficients by 2:

2Ca(NO3)2 + 7H2SO4 → 2CaSO4 + 4HNO3

Now, the equation is balanced with respect to the individual elements.