What is the equation in point-slope form of the line that passes through the point (-2, 4) and has a slope of 3
The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope.
In this case, the point is (-2, 4) and the slope is 3.
Substituting these values into the point-slope form equation, we have:
y - 4 = 3(x - (-2))
Simplifying,
y - 4 = 3(x + 2)
y - 4 = 3x + 6
Finally, rearranging the equation to the standard form, we get:
3x - y = -10
So, the equation in point-slope form of the line that passes through the point (-2, 4) and has a slope of 3 is y - 4 = 3(x + 2), and in standard form, it is 3x - y = -10.