Find the surface area of a rectangular pyramid with these measurements: l = 8 cm, w = 4 cm, and h = 2 cm. Express your answer as a decimal rounded to the nearest hundredth.(1 point)
To find the surface area of a rectangular pyramid, you need to find the area of the base and the area of each of the four triangular faces.
The area of the base can be found by multiplying the length and width:
area of base = l * w
= 8 cm * 4 cm
= 32 cm^2
The area of each triangular face can be found by multiplying the base of the triangle (which is the same as the length of the pyramid) by the height of the triangle (which is the same as the height of the pyramid) and then dividing by 2:
area of each triangular face = (l * h) / 2
= (8 cm * 2 cm) / 2
= 16 cm^2 / 2
= 8 cm^2
Since there are four triangular faces, the total area of all the triangular faces is 4 * 8 cm^2 = 32 cm^2.
Therefore, the total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces:
total surface area = area of base + area of triangular faces
= 32 cm^2 + 32 cm^2
= 64 cm^2
Therefore, the surface area of the rectangular pyramid is 64 cm^2.