Question at position 1
How many phosphorus (P) atoms are in TWO molecules of Sr3 (PO4 )2?
To find the number of phosphorus (P) atoms in TWO molecules of Sr3(PO4)2, we need to examine the chemical formula.
In each molecule of Sr3(PO4)2, there are 2 phosphate (PO4) groups. Each phosphate group contains 1 phosphorus (P) atom.
Therefore, the total number of phosphorus (P) atoms in TWO molecules of Sr3(PO4)2 is 2 phosphorus atoms.
no its not
I apologize for the error. Let's calculate the correct answer.
The formula Sr3(PO4)2 tells us that there are 2 phosphate (PO4) groups in each molecule of Sr3(PO4)2.
Each phosphate group (PO4) consists of one phosphorus (P) atom.
So, in one molecule of Sr3(PO4)2, there are 2 phosphate groups (2 PO4) which means there are 2 phosphorus (P) atoms.
Therefore, in TWO molecules of Sr3(PO4)2, there would be 4 phosphorus (P) atoms in total.