The pair of points (6, y) and (10, –1) lie on a line with slope one-fourth. What is the value of y?
(1 point)
–5
–5
–2
–2
2
2
5
To find the value of y, we can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept.
Given that the slope is one-fourth and one of the points on the line is (10, -1), we can substitute these values into the equation:
-1 = (1/4)(10) + b
Simplifying, we have:
-1 = 5/2 + b
To isolate b, we subtract 5/2 from both sides:
-3/2 = b
Therefore, the value of y when x = 6 is -3/2.