# Solve x^2+2x=-2 by graphing and indicate the roots.Please and thank you

We can't draw graphs for you here.
The roots are x = -2.73 and -0.73
I suggest you make your own graph of
y = x^2 + 2x and see where it crosses the horizontal line y = -2.
Choose x values of -4, -3, -2, -1, 0 and 1.

## To solve the equation by graphing and determine the roots, follow these steps:

1. Sketch the graph of the equation y = x^2 + 2x.

Start by creating a coordinate system with the x and y axes. Plot a few points on the graph to help you visualize the shape of the function. One way to do this is to choose values for x (e.g., -4, -3, -2, -1, 0, 1) and calculate the corresponding y values using the equation y = x^2 + 2x. For example, when x = -4, y = (-4)^2 + 2(-4) = 16 - 8 = 8. Plot the points (-4, 8), (-3, 3), (-2, -2), (-1, -1), (0, 0), and (1, 3) on the graph.

2. Draw the horizontal line y = -2 on the same graph.

This line represents the value of y that we want the graph of our equation to intersect. Draw a straight line horizontally at y = -2.

3. Look for the points where the graph and the horizontal line intersect.

Examine the graph to find the points where the graph of y = x^2 + 2x crosses the horizontal line y = -2. These points indicate the roots or solutions of the equation x^2 + 2x = -2. In this case, you will find two intersections: one near x = -2.73 and another near x = -0.73.

By using the above steps, you should be able to solve the equation and indicate the roots by graphing.