# 'L' has y-intercept (0,-3) and is parallel to the line with equation y=2/3x+1.

(Instructions - write the equation of the line 'L' satisfying the given geometric conditions)

We know that two lines that are parallel must have the same slope. So this line must have the slope (2/3), like the other liner equation.

Then use the equation

y= mx +b

You have the slope now and the y-inercept is given.

so...

the equation is

'L' = (2/3)x - 3

## To find the equation of line 'L' that is parallel to the line y = (2/3)x + 1 and passes through the y-intercept (0, -3), you can use the slope-intercept form of a linear equation, which is y = mx + b.

Given that the slope of line 'L' is the same as the given line (2/3), and the y-intercept is (0, -3), we can substitute these values into the slope-intercept form.

So the equation of line 'L' would be y = (2/3)x - 3.