The 2,3,4 term of a ap are (x-2),5,(X+2) find the value of X and 9 term
We are given that the second term of the arithmetic progression (AP) is 5.
The formula for the nth term of an AP is given by:
a_n = a_1 + (n-1)d
where a_n is the nth term of the AP, a_1 is the first term, n is the position of the term, and d is the common difference.
We can use this formula to find the value of x.
Given that the second term is 5:
5 = x - 2 + (2-1)d
5 = x - 2 + d (since d = 2-1 = 1)
Simplifying the equation, we have:
5 = x - 2 + 1
5 = x - 1
Adding 1 to both sides, we get:
6 = x
Therefore, the value of x is 6.
Now, we can find the 9th term of the AP.
Using the same formula, we have:
a_9 = a_1 + (9-1)d
a_9 = x - 2 + (9-1)d
a_9 = x - 2 + 8d
a_9 = 6 - 2 + 8d (since x = 6)
Simplifying the equation, we have:
a_9 = 4 + 8d
Since we are not given the common difference d, we cannot calculate the 9th term without further information.