If 15.0 g of Pb(s) reacts in a car battery, the amount of energy released is
delta H is -315.9 KJ
To find the amount of energy released during the reaction, we need to first calculate the moles of Pb(s) reacted.
The molar mass of lead (Pb) is 207.2 g/mol.
Number of moles of Pb(s) = 15.0 g / 207.2 g/mol = 0.0724 mol
Now that we have the moles of Pb(s) reacted, we can calculate the energy released using the equation:
Energy released = moles of Pb(s) reacted * ΔH
Energy released = 0.0724 mol * -315.9 KJ
Energy released = -22.89 KJ
Therefore, 15.0 g of Pb(s) will release 22.89 KJ of energy.