If the period of a simple pendulum is to be 3.91 s, what should be its length?
The period of a simple pendulum is given by the formula:
T = 2π√(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Rearranging the formula to solve for L:
L = (T/2π)² * g
Substituting the given values:
L = (3.91 s / (2π))² * 9.8 m/s²
Calculating the length:
L ≈ (0.621 s)² * 9.8 m/s²
L ≈ 2.446 m
Therefore, the length of the simple pendulum should be approximately 2.446 meters.