Laura has 16 pygmy goats and 28 dairy goats. When she goes to the county fair, she needs to put them in pens with no two types of goats sharing a pen. She also needs the same number of goats in each pen. How many goats will she put in each pen
To find the number of goats in each pen, Laura needs to find the common factors of 16 and 28. The factors of 16 are 1, 2, 4, 8, and 16. The factors of 28 are 1, 2, 4, 7, 14, and 28. The common factors are 1, 2, and 4. Therefore, Laura will put either 1, 2, or 4 goats in each pen.
Laura has 16 pygmy goats and 28 dairy goats. When she goes to the county fair, she needs to put them in pens with no two types of goats sharing a pen. She also needs the same number of goats in each pen. How many goats will she put in each pen?
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1 point
2 goats
4 goats
112 goats
448 goats
In order for Laura to have the same number of goats in each pen and not have two types of goats in the same pen, she needs to find the greatest common divisor (GCD) of 16 and 28. The GCD of 16 and 28 is 4. so Laura will put 4 goats in each pen.
Rewrite 135 + 45 in the form a (b + c) where a is the greatest common factor of 135 and 45.
To rewrite 135 + 45 in the form a (b + c), we need to find the greatest common factor (GCF) of 135 and 45.
The prime factorization of 135 is 3^3 * 5.
The prime factorization of 45 is 3^2 * 5.
The common factors of 135 and 45 are 3^2 * 5, which is equal to 45.
Therefore, we can rewrite 135 + 45 as:
a (b + c) = 45 (3 + 1) = 45 * 4 = 180.
Rewrite the following numerical expression in an equivalent form using the distributive property: 36 + 54. Select all that apply.*3 points3 (12 + 18)3 (12 + 54)6 (6 + 9)6 (6 + 54)9 (4+ 6)9 (4 + 54)
To rewrite the numerical expression 36 + 54 using the distributive property, we can factor out a common factor and distribute it to each term.
36 + 54 = 6 * 6 + 6 * 9
From the given options, the equivalent form using the distributive property is:
6 (6 + 9)