Calculate the mass of sulphuric acid in 25cmof solution whose concentration is 0.25mol/dm
To calculate the mass of sulfuric acid in 25cm of solution, we need to know the molar mass of sulfuric acid, which is H2SO4.
The molar mass of hydrogen (H) is 1.01 g/mol, the molar mass of sulfur (S) is 32.07 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.
The molar mass of sulfuric acid (H2SO4) can be calculated as follows:
(2 * molar mass of hydrogen) + molar mass of sulfur + (4 * molar mass of oxygen)
= (2 * 1.01 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol)
= 2.02 g/mol + 32.07 g/mol + 64.00 g/mol
= 98.09 g/mol
The concentration of the solution is given as 0.25 mol/dm³. This means that there are 0.25 moles of sulfuric acid in 1 dm³ (1000 cm³) of solution.
To find the mass of sulfuric acid in 25 cm³ of solution, we can use the following equation:
Mass of sulfuric acid = (0.25 mol/dm³) * (25 cm³) * (98.09 g/mol) / (1000 cm³/dm³)
= (0.25) * (25) * (98.09) / (1000)
= 6.12725 g
Therefore, the mass of sulfuric acid in 25 cm³ of solution with a concentration of 0.25 mol/dm³ is approximately 6.13 grams.