Find the volume of a sphere with a radius of 3 m. Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.,
To find the volume of a sphere, we can use the formula V = (4/3) * pi * r^3, where r is the radius of the sphere. Given that the radius is 3 m and pi is approximately equal to 3.14, we can substitute these values into the formula.
V = (4/3) * 3.14 * (3)^3
V = (4/3) * 3.14 * 27
V = 113.04
Rounded to the nearest hundredth, the volume of the sphere is approximately 113.04 cubic meters.
Find the volume of a sphere with a diameter 12 m. Leave your answer in terms of pi.
The formula for the volume of a sphere is given by V = (4/3) * pi * r^3, where r is the radius of the sphere. Since we're given the diameter (which is twice the radius), we can calculate the radius by dividing the diameter by 2.
radius = diameter/2 = 12 m / 2 = 6 m
Now, we can substitute the radius into the formula:
V = (4/3) * pi * (6 m)^3
V = (4/3) * pi * 216 m^3
Therefore, the volume of the sphere with a diameter of 12 m is 288 * pi cubic meters.
How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi. Round your answer to the nearest hundredth, if necessary.
To find the volume of the spherical chocolate truffle, we can use the formula V = (4/3) * pi * r^3, where r is the radius. Given that the radius is 12 mm and pi is approximately equal to 3.14, we can substitute these values into the formula.
V = (4/3) * 3.14 * (12 mm)^3
V = (4/3) * 3.14 * (1728 mm^3)
V = 7234.56 mm^3
Rounded to the nearest hundredth, the volume of the chocolate truffle is approximately 7234.56 mm^3.
The volume of a container measures 3,200 in.3 and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary.
To find the volume of a single tennis ball, we can use the formula V = (4/3) * pi * r^3, where r is the radius of the tennis ball. Given that the radius is 2.5 in and pi is approximately equal to 3.14, we can substitute these values into the formula.
V = (4/3) * 3.14 * (2.5 in)^3
V = (4/3) * 3.14 * (15.625 in^3)
V = 65.45 in^3
Now, to find the total volume occupied by a dozen tennis balls, we can multiply the volume of a single tennis ball by 12.
Total volume occupied by tennis balls = 65.45 in^3 * 12 = 785.4 in^3
To find the empty space in the container, we can subtract the total volume occupied by the tennis balls from the volume of the container.
Empty space in container = 3200 in^3 - 785.4 in^3 = 2414.6 in^3
Rounded to the nearest whole number, the empty space in the container is approximately 2415 in^3.