The pair of points -6, y and 4,8lie on a line with a slope of 5/2 . The formula used to solve for the slope of a line is Response area. The correct set-up of this problem8-y/4-(-6) is = Response area. When solving this problem, in order to get the variable y out of the numerator, you must Response area. The correct value for the missing y is Response area.
The correct set-up of this problem is (8-y)/(4-(-6)).
In order to get the variable y out of the numerator, we can distribute the negative sign to (-(-6)) and simplify:
(8-y)/(4+6) = (8-y)/10
The slope of a line is calculated as the change in y divided by the change in x. In this case, the change in y is 8-y and the change in x is 4-(-6), which simplifies to 4+6=10.
So, the slope of the line is (8-y)/10 = 5/2.
To solve for y, we can cross-multiply:
2(8-y) = 5(10)
16-2y = 50
-2y = 50-16
-2y = 34
y = 34/(-2)
y = -17
The correct value for the missing y is -17.