Calculate the mass of sulphuric acid in 250cm of solution whose concentration is 0.25Mol/dm
To calculate the mass of sulphuric acid in the solution, we need to know the molar mass of sulphuric acid, which is H2SO4?
The molar mass of sulphuric acid is:
(2*1.008 g/mol) + (32.07 g/mol) + (4*16.00 g/mol) = 98.09 g/mol
To calculate the number of moles of sulphuric acid in the solution, we use the formula:
moles = concentration (mol/dm³) x volume (dm³)
Given:
concentration = 0.25 mol/dm³
volume = 250 cm³
First, we need to convert the volume from cm³ to dm³:
volume = 250 cm³ x (1 dm³ / 1000 cm³) = 0.25 dm³
Now, calculate the number of moles:
moles = 0.25 mol/dm³ x 0.25 dm³ = 0.0625 mol
Finally, calculate the mass of sulphuric acid in grams:
mass = moles x molar mass = 0.0625 mol x 98.09 g/mol = 6.13 g
Therefore, the mass of sulphuric acid in 250 cm³ of a 0.25 M solution is 6.13 grams.