Which is the equation of the line that passes through the points (-9, -14) and (3, 2)
To find the equation of the line that passes through the points (-9, -14) and (3, 2), we need to find the slope of the line first.
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
slope = (y2 - y1) / (x2 - x1)
Plugging in the given points, we get:
slope = (2 - (-14)) / (3 - (-9))
slope = 16 / 12
slope = 4 / 3
We have the slope of the line, now we just need to find the y-intercept (b).
Using the point-slope form of a linear equation (y - y1) = m(x - x1), where m is the slope and (x1, y1) is a point on the line, we can plug in one of the points to solve for the y-intercept (b).
Let's use the point (3, 2):
(y - 2) = (4/3)(x - 3) [plug in the values]
y - 2 = (4/3)x - 4 [simplify]
y = (4/3)x - 2
So the equation of the line that passes through the points (-9, -14) and (3, 2) is y = (4/3)x - 2.