Find the resultant of two vector of 3unit and 4 unit at a point 0⁰ at an angle of 45⁰ with each other
To find the resultant of two vectors at a specific angle, we can use the vector addition formula.
Let's call the first vector A with magnitude 3 units and the second vector B with magnitude 4 units.
The angle between the two vectors is 45 degrees.
To find the resultant, we can use the formula:
R = √(A^2 + B^2 + 2ABcosθ)
where R is the magnitude of the resultant vector, A and B are the magnitudes of the individual vectors, and θ is the angle between the two vectors.
Plugging in the values:
R = √(3^2 + 4^2 + 2*3*4*cos(45))
R = √(9 + 16 + 24cos(45))
R = √(25 + 24*0.7071)
R = √(25 + 16.9704)
R = √(41.9704)
R ≈ 6.48 units
So, the magnitude of the resultant vector is approximately 6.48 units.