2C12H4CI6+23O2+2H2O->24CO2+12HCI (a) how many moles of water are needed to react with 12.8 mol O2? Mol H2O
To determine the number of moles of water needed to react with 12.8 mol of O2, we need to look at the balanced chemical equation.
From the equation:
2C12H4CI6 + 23O2 + 2H2O → 24CO2 + 12HCI
We can see that for every 2 moles of H2O, 23 moles of O2 are needed to react.
This means that the mole ratio of H2O to O2 is 2:23.
To find the number of moles of H2O needed, we can set up a proportion:
2 mol H2O / 23 mol O2 = x mol H2O / 12.8 mol O2
Cross-multiplying, we get:
23 mol O2 * x mol H2O = 2 mol H2O * 12.8 mol O2
23x = 25.6
Dividing both sides by 23, we find:
x = 1.113 mol H2O
Therefore, 1.113 moles of water are needed to react with 12.8 mol of O2.